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32400=-12x^2+1440x
We move all terms to the left:
32400-(-12x^2+1440x)=0
We get rid of parentheses
12x^2-1440x+32400=0
a = 12; b = -1440; c = +32400;
Δ = b2-4ac
Δ = -14402-4·12·32400
Δ = 518400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{518400}=720$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1440)-720}{2*12}=\frac{720}{24} =30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1440)+720}{2*12}=\frac{2160}{24} =90 $
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